Exercise algebra.equations.quadratic.approximate

Description
solve a quadratic equation with approximation

Examples

easy (10)

x^2 == 2

x^2+3 == 52

x^2-7 == 0

9*x^2-6 == 75

32-2*x^2 == 14

2*(x^2-3) == 12

1/4*x^2+12 == 16

(x-1)^2 == 100

14-2*x^2 == 6

1/4*(17-x^2) == 2

medium (30)

(x-7)^2+3 == 11

(6-2*x)^2 == 81

1/2*(x+9)^2 == 4

(3-x^2)/10 == 2

5*x^2+3*x == 3*x+2

11-(2*x+1)^2 == 5

(6*x-3)^2+6 == 12

(7+2*x)^2 == 7

4-x^2/10 == 6

12-(2*x+3)^2 == 6

x^2 == 5*x

x^2-6*x == 0

6*x+x^2 == 0

x*(x+4) == 0

x*(2*x-4) == 0

3*x^2 == 6*x

3*x == 2*x^2

x*(1-6*x) == 0

(x+5)*(x-8) == 0

(3*x-1)*(x+3) == 0

x^2-2*x == 3

x^2+12*x+20 == 0

x^2-x == 30

x*(x+2) == 8

x*(x-3) == 4

2*x+15 == x^2

4*x == 12-x^2

x^2 == 15-8*x

x^2-9*x+18 == 0

x^2+14*x+24 == 0

difficult (20)

(3*x+5)^2+(x-5)^2 == 40

4*(10-x^2) == -2*x*(2*x+10)

x*(x+12) == 2*x^2

3*(x-2)*(x+6) == 12*x

8*x^2+4*x-24 == (x+3)*(x-8)

3*x^2-11 == (3+2*x)^2

2*x*(x-3)-3 == (x+2)*(x+6)

12*(x^2-3*x)+8 == 56

4*x^2-6*x == x^2+9

(x+1)*(x-5) == (x-2)*(x-3)

x^2+4*x-4 == 0

x^2-6*x == 4

x^2-12*x+34 == 0

2*x^2+4*x-8 == 0

(x-4)*(x-1) == 11

(x-7/2)^2 == 2*(x+4)

x^2-3*x == 3*(x-2)

(4-x)*(1-x) == 3*x

2*x^2 == x*(x+2)+7

(1-x)^2 == x+2